Integrand size = 19, antiderivative size = 57 \[ \int \frac {\left (d+e x^2\right ) (a+b \arctan (c x))}{x^2} \, dx=-\frac {d (a+b \arctan (c x))}{x}+e x (a+b \arctan (c x))+b c d \log (x)-\frac {b \left (c^2 d+e\right ) \log \left (1+c^2 x^2\right )}{2 c} \]
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Time = 0.05 (sec) , antiderivative size = 57, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.211, Rules used = {14, 5096, 457, 78} \[ \int \frac {\left (d+e x^2\right ) (a+b \arctan (c x))}{x^2} \, dx=-\frac {d (a+b \arctan (c x))}{x}+e x (a+b \arctan (c x))-\frac {b \left (c^2 d+e\right ) \log \left (c^2 x^2+1\right )}{2 c}+b c d \log (x) \]
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Rule 14
Rule 78
Rule 457
Rule 5096
Rubi steps \begin{align*} \text {integral}& = -\frac {d (a+b \arctan (c x))}{x}+e x (a+b \arctan (c x))-(b c) \int \frac {-d+e x^2}{x \left (1+c^2 x^2\right )} \, dx \\ & = -\frac {d (a+b \arctan (c x))}{x}+e x (a+b \arctan (c x))-\frac {1}{2} (b c) \text {Subst}\left (\int \frac {-d+e x}{x \left (1+c^2 x\right )} \, dx,x,x^2\right ) \\ & = -\frac {d (a+b \arctan (c x))}{x}+e x (a+b \arctan (c x))-\frac {1}{2} (b c) \text {Subst}\left (\int \left (-\frac {d}{x}+\frac {c^2 d+e}{1+c^2 x}\right ) \, dx,x,x^2\right ) \\ & = -\frac {d (a+b \arctan (c x))}{x}+e x (a+b \arctan (c x))+b c d \log (x)-\frac {b \left (c^2 d+e\right ) \log \left (1+c^2 x^2\right )}{2 c} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 73, normalized size of antiderivative = 1.28 \[ \int \frac {\left (d+e x^2\right ) (a+b \arctan (c x))}{x^2} \, dx=-\frac {a d}{x}+a e x-\frac {b d \arctan (c x)}{x}+b e x \arctan (c x)+b c d \log (x)-\frac {1}{2} b c d \log \left (1+c^2 x^2\right )-\frac {b e \log \left (1+c^2 x^2\right )}{2 c} \]
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Time = 0.09 (sec) , antiderivative size = 74, normalized size of antiderivative = 1.30
method | result | size |
derivativedivides | \(c \left (\frac {a \left (e c x -\frac {d c}{x}\right )}{c^{2}}+\frac {b \left (\arctan \left (c x \right ) e c x -\frac {\arctan \left (c x \right ) d c}{x}-\frac {\left (c^{2} d +e \right ) \ln \left (c^{2} x^{2}+1\right )}{2}+d \,c^{2} \ln \left (c x \right )\right )}{c^{2}}\right )\) | \(74\) |
default | \(c \left (\frac {a \left (e c x -\frac {d c}{x}\right )}{c^{2}}+\frac {b \left (\arctan \left (c x \right ) e c x -\frac {\arctan \left (c x \right ) d c}{x}-\frac {\left (c^{2} d +e \right ) \ln \left (c^{2} x^{2}+1\right )}{2}+d \,c^{2} \ln \left (c x \right )\right )}{c^{2}}\right )\) | \(74\) |
parts | \(a \left (e x -\frac {d}{x}\right )+b c \left (\frac {\arctan \left (c x \right ) x e}{c}-\frac {\arctan \left (c x \right ) d}{c x}-\frac {-d \,c^{2} \ln \left (c x \right )+\frac {\left (c^{2} d +e \right ) \ln \left (c^{2} x^{2}+1\right )}{2}}{c^{2}}\right )\) | \(76\) |
parallelrisch | \(\frac {2 b \,c^{2} d \ln \left (x \right ) x -\ln \left (c^{2} x^{2}+1\right ) b \,c^{2} d x +2 x^{2} \arctan \left (c x \right ) b c e +2 a e \,x^{2} c -\ln \left (c^{2} x^{2}+1\right ) b e x -2 \arctan \left (c x \right ) b c d -2 a d c}{2 c x}\) | \(87\) |
risch | \(\frac {i b \left (-e \,x^{2}+d \right ) \ln \left (i c x +1\right )}{2 x}+\frac {i b c e \,x^{2} \ln \left (-i c x +1\right )+2 b \,c^{2} d \ln \left (x \right ) x -\ln \left (c^{2} x^{2}+1\right ) b \,c^{2} d x -i b c d \ln \left (-i c x +1\right )+2 a e \,x^{2} c -\ln \left (c^{2} x^{2}+1\right ) b e x -2 a d c}{2 c x}\) | \(121\) |
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Time = 0.25 (sec) , antiderivative size = 74, normalized size of antiderivative = 1.30 \[ \int \frac {\left (d+e x^2\right ) (a+b \arctan (c x))}{x^2} \, dx=\frac {2 \, b c^{2} d x \log \left (x\right ) + 2 \, a c e x^{2} - 2 \, a c d - {\left (b c^{2} d + b e\right )} x \log \left (c^{2} x^{2} + 1\right ) + 2 \, {\left (b c e x^{2} - b c d\right )} \arctan \left (c x\right )}{2 \, c x} \]
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Time = 0.33 (sec) , antiderivative size = 80, normalized size of antiderivative = 1.40 \[ \int \frac {\left (d+e x^2\right ) (a+b \arctan (c x))}{x^2} \, dx=\begin {cases} - \frac {a d}{x} + a e x + b c d \log {\left (x \right )} - \frac {b c d \log {\left (x^{2} + \frac {1}{c^{2}} \right )}}{2} - \frac {b d \operatorname {atan}{\left (c x \right )}}{x} + b e x \operatorname {atan}{\left (c x \right )} - \frac {b e \log {\left (x^{2} + \frac {1}{c^{2}} \right )}}{2 c} & \text {for}\: c \neq 0 \\a \left (- \frac {d}{x} + e x\right ) & \text {otherwise} \end {cases} \]
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Time = 0.18 (sec) , antiderivative size = 73, normalized size of antiderivative = 1.28 \[ \int \frac {\left (d+e x^2\right ) (a+b \arctan (c x))}{x^2} \, dx=-\frac {1}{2} \, {\left (c {\left (\log \left (c^{2} x^{2} + 1\right ) - \log \left (x^{2}\right )\right )} + \frac {2 \, \arctan \left (c x\right )}{x}\right )} b d + a e x + \frac {{\left (2 \, c x \arctan \left (c x\right ) - \log \left (c^{2} x^{2} + 1\right )\right )} b e}{2 \, c} - \frac {a d}{x} \]
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\[ \int \frac {\left (d+e x^2\right ) (a+b \arctan (c x))}{x^2} \, dx=\int { \frac {{\left (e x^{2} + d\right )} {\left (b \arctan \left (c x\right ) + a\right )}}{x^{2}} \,d x } \]
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Time = 0.26 (sec) , antiderivative size = 69, normalized size of antiderivative = 1.21 \[ \int \frac {\left (d+e x^2\right ) (a+b \arctan (c x))}{x^2} \, dx=a\,e\,x-\frac {a\,d}{x}+b\,e\,x\,\mathrm {atan}\left (c\,x\right )-\frac {b\,c\,d\,\ln \left (c^2\,x^2+1\right )}{2}+b\,c\,d\,\ln \left (x\right )-\frac {b\,d\,\mathrm {atan}\left (c\,x\right )}{x}-\frac {b\,e\,\ln \left (c^2\,x^2+1\right )}{2\,c} \]
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